DSSSB TGT Computer Science Exam Pattern and Marking Scheme: Sections, Scores and Timing

Understand how Section A and Section B contribute to the historical 39/22 scheme. Work through the negative-marking calculation, distinguish qualification from merit, and plan a timed mock.

KnowledgeGate Team

Exam prep & CS education

30 Sep 20264 min read137 views

You may know Computer Science well and still be unsure whether general aptitude affects selection or how wrong answers reduce your score. This guide maps the sections and works through a complete raw-score calculation.

Scope: The numerical reference is post code 39/22 under Advertisement 08/22, dated 14 October 2022, with the qualification and merit distinction corroborated by the notice dated 27 February 2024. These are historical documents; match your own post code and notification before applying this scheme to another recruitment cycle.

Match the exam pattern to your DSSSB post code

Start with three fields: post title, post code and advertisement number. For this reference, they are TGT Computer Science / 39/22 / 08/22. Each teaching post has its own examination scheme.

Advertisement 08/22 places this post in the one-tier teaching examination scheme.

When choosing government teaching exam preparation, select resources for your exact post. The preparation catalog separates general subjects and Computer Science, but official examination rules come from the matching advertisement and instructions.

Read the two-section paper at a glance

DSSSB's Advertisement 08/22 dated 14 October 2022, examination scheme row A and its notes, specified the section marks and overall question count for post code 39/22. Each MCQ carried one mark, so the table derives 20 questions for each 20-mark Section A component.

Section

Component

Questions

Marks

A

General Awareness

20

20

A

General Intelligence and Reasoning Ability

20

20

A

Arithmetical and Numerical Ability

20

20

A

Hindi Language and Comprehension

20

20

A

English Language and Comprehension

20

20

A

Subtotal

100

100

B

Subject concerned: Computer Science

100

100

Grand total

200

200

The duration was two hours, or 120 minutes.

These are two sections within one paper. Organise preparation around the 100 marks for general subjects and 100 marks for Computer Science.

Know what each section means for preparation

Section A needs regular work on language accuracy, arithmetic, reasoning and awareness. Section B needs organised Computer Science revision. Programming, data structures, operating systems, DBMS and computer networks are useful preparation areas covered by the subject course.

Keep separate revision queues. A Hindi comprehension error needs passage-reading practice; an OS scheduling error needs a corrected scheduling trace and another problem. Both affect the aggregate, so match each revision task to the error.

Use the DSSSB Section B syllabus breakdown to organise subject study.

Calculate negative marking with a complete mock example

Under the historical scheme above, a correct answer earns 1 mark, and a wrong MCQ loses 0.25 marks. For this practice calculation, unanswered items contribute zero, all questions and the answer key are treated as final.

Raw mock score = C − 0.25W, where C is correct answers and W is wrong answers.

Section

Correct

Wrong

Unattempted

Raw-score calculation

A

70

20

10

70 − (20 × 0.25) = 70 − 5 = 65

B

75

15

10

75 − (15 × 0.25) = 75 − 3.75 = 71.25

Combined

145

35

20

145 − (35 × 0.25) = 145 − 8.75 = 136.25

Check the counts: Section A has 70 + 20 + 10 = 100 items; Section B has 75 + 15 + 10 = 100. Together, 145 + 35 + 20 = 200, with 145 + 35 = 180 attempted.

Four wrong answers deduct 4 × 0.25 = 1 mark from the correct-answer tally. Changing one wrong response into a correct response improves the score by 1 − (−0.25) = 1.25 marks. The 136.25/200 here is an illustrative raw mock score.

Separate qualifying marks, merit and normalisation

Paragraph 5 of the 27 February 2024 post-code-specific notice confirms that, for 39/22, mandatory minimum qualification applied only to Section B. Section A had no minimum qualifying marks, but both sections contributed to final merit.

That makes Section A worth studying. In our example, 65 + 71.25 = 136.25 raw marks. Check Section B against the applicable category requirement, then assess the combined score for merit.

The advertisement allows normalisation if required and prorating when questions are invalidated. The later notice reports normalised section scores out of 100 each and a total out of 200. A home calculation therefore gives a raw estimate before official processing.

Rehearse a realistic 120-minute attempt plan

For practice using this historical format, try an author-designed split, subject to applicable navigation instructions: 45 minutes for Section A, 60 for Section B and 15 for reviewing flagged items. That is 45 + 60 + 15 = 120 minutes.

The overall average is 120 × 60 ÷ 200 = 36 seconds per question, including review. Reserving 15 minutes leaves 105 minutes; the first-pass average becomes 105 × 60 ÷ 200 = 31.5 seconds per item.

These averages show why getting stuck costs opportunities elsewhere. Allow more time for demanding questions and move quickly through familiar ones. Track time lost and wrong answers by section, then adjust the split after timed mocks. The DSSSB Section A study plan helps make general-subject practice repeatable.

Turn the pattern into your next study session

Verify your post-code scheme, corrigenda and examination instructions on the official DSSSB website. Complete one timed mock under those rules, then classify lost marks into knowledge gaps, calculation or reading errors, and time pressure.

For CS gaps exposed by Section B, use the DSSSB TGT Computer Science Section B course as structured subject preparation. Revise the weak topic and solve fresh questions before the next mock, so your score review leads to a specific study task.