Read the information and answer the following question. The table shows the…
2023
Read the information and answer the following question.
The table shows the number of males working in private and public companies and the number of females working in private and public company in four (A, B, C & D) different cities.
Note –
(i) Number of male employees in A are 50.
(ii) Total males working in private company from B and C are 154.
(iii) Total employees (male + female) working in any city = private companies + public company.
(iv) Males/females working in any city = Sum of males/females working in private and public company.
Males working in city C is approximately what percentage of females working in B?
- A.
80%
- B.
190%
- C.
180%
- D.
106%
- E.
70%
Show answer & explanation
Correct answer: D
Concept
In a data-interpretation table whose cells are written as algebraic expressions, you first recover the unknown letters by turning the given external conditions into simultaneous linear equations, solve them, and only then substitute the values back into the cell expressions to read off any required quantity. A “what percentage of” question is simply (part ÷ whole) × 100, where the “whole” is the quantity that follows the words “percentage of”.
Males in a city = males in private company + males in public company; females in a city are given directly in the last column.
Application
Use Note (i): total males in city A = (15x − 2y) + y = 15x − y = 50.
Use Note (ii): males in private company from B and C = 16x + 9y = 154.
From the first equation, y = 15x − 50. Substitute into the second: 16x + 9(15x − 50) = 154 → 16x + 135x − 450 = 154 → 151x = 604 → x = 4.
Back-substitute: y = 15(4) − 50 = 60 − 50 = 10.
Males in city C = (private) 9y + (public) 24 = 9(10) + 24 = 90 + 24 = 114.
Females in city B = 108 (read directly from the last column).
Required percentage = (114 ÷ 108) × 100 = 105.56%, which is approximately 106%.
Cross-check
Verify the solved values against every condition: males in A = (15·4 − 2·10) + 10 = 40 + 10 = 50 ✓; males in private from B and C = 16·4 + 9·10 = 64 + 90 = 154 ✓. Both notes hold, so x = 4 and y = 10 are correct.