Direction : Given below table shows total three types of items (A, B & C) sold…
2020
Direction : Given below table shows total three types of items (A, B & C) sold by a store on five
days of a week. Table also shows total type A items sold by store and percentage of items B and items C
sold by store. Read the data carefully and answer following questions:
Note- only three types of items sold by the store.
Find the difference between average number of items B sold by store on Tuesday & Thursday and average number of items A sold by store on Thursday & Friday?
- A.
260
- B.
264
- C.
262
- D.
272
- E.
268
Show answer & explanation
Correct answer: C
Concept: When a store sells only three item types A, B and C, the day's total equals A + B + C. If B and C are given as percentages of that total, then A is the remaining share: A = Total × (1 − %B − %C). Rearranging gives the total for any day as Total = A ÷ (1 − %B − %C), and once the total is known each count is just its percentage of it (B = %B × Total).
Application:
Tuesday: A = 320, %B = 48%, %C = 12%, so %A = 100% − 48% − 12% = 40%. Total = 320 ÷ 0.40 = 800. Therefore B(Tue) = 48% × 800 = 384.
Thursday: A = 360, %B = 56%, %C = 20%, so %A = 100% − 56% − 20% = 24%. Total = 360 ÷ 0.24 = 1500. Therefore B(Thu) = 56% × 1500 = 840.
Average number of B sold on Tuesday and Thursday = (384 + 840) ÷ 2 = 1224 ÷ 2 = 612.
Average number of A sold on Thursday and Friday = (360 + 340) ÷ 2 = 700 ÷ 2 = 350. (Items A are read directly from the table, so no percentage step is needed here.)
Required difference = 612 − 350 = 262.
Cross-check: Recover the totals independently — Tuesday 0.40 × 800 = 320 = A(Tue) and Thursday 0.24 × 1500 = 360 = A(Thu), so the totals are consistent with the given A values. The two B counts 384 and 840 average to 612, and the two directly-read A counts 360 and 340 average to 350, leaving a gap of 262.