Directions : Read the data carefully and answer the questions. Some data are…
2019
Directions : Read the data carefully and answer the questions. Some data are missing which you have to calculate as per information provided in the questions.
NOTE:- A duplicate applicant is an applicant who has submitted additional (duplicate) application after submitting their original application. All application forms (original + duplicate) received from duplicate applicant were rejected. Remaining all application were accepted. None of the applicants applied for more than one post.
If average no. of accepted applications for position A & B is 659. What is the value of rejected applications for position B?
- A.
287
- B.
246
- C.
254
- D.
275
- E.
263
Attempted by 1 students.
Show answer & explanation
Correct answer: A
Concept
A duplicate applicant submits one original plus some extra (duplicate) forms, and ALL of their forms — original and duplicates — are rejected. So for any position:
Rejected = (duplicate applicants) × (1 original + average duplicate forms per applicant)
and Accepted = (applications received) − Rejected. The given average of accepted applications fixes the combined accepted total, which lets us isolate the unknown side.
Application
Position A rejected: each of the 63 duplicate applicants files 1 original + 4 duplicates = 5 forms, all rejected → 63 × 5 = 315.
Position A accepted: 1040 received − 315 rejected = 725.
Combined accepted (A + B): average 659 for two positions → 659 × 2 = 1318.
Position B accepted: 1318 − 725 = 593.
Position B rejected: 880 received − 593 accepted = 287.
Cross-check
Rebuild the combined accepted total from the two sides: 725 (A) + 593 (B) = 1318, and 1318 ÷ 2 = 659, which is exactly the stated average. The rejected value for B is 287.