For a real number x > 1, \[\frac{1}{\log_{2}x}+\frac{1}{\log_{3}x}+\frac{1}{\lo…

For a real number x > 1,

$$\frac{1}{\log_{2}x}+\frac{1}{\log_{3}x}+\frac{1}{\log_{4}x}=1$$

The value of x is