A, B, C, D, E, F and G are sitting around a circular table facing the centre.…
2025
A, B, C, D, E, F and G are sitting around a circular table facing the centre. Only two
people sit between F and D when counted from the right of F. Only three people sit
between B and G when counted from the right of G. D sits to the immediate right of G. E
sits to the immediate right of A. How many people sit between C and E when counted
from the right of E?
- A.
2
- B.
4
- C.
1
- D.
3
Show answer & explanation
Correct answer: A
Concept
When everyone at a circular table faces the centre, 'right' and 'left' point in one single, fixed rotational sense for every person seated there. So a clue such as "k people sit between X and Y, counted from the right of X" fixes Y at exactly k + 1 seats to the right of X. Solving the puzzle means writing every person's seat as an offset (mod 7, for seven people) from one fixed reference seat, then finding the single assignment that satisfies every offset at once.
Application
Fix G at seat 0 and let one step "to the right" mean +1 (mod 7); this one rotational sense applies to every person at the table.
"D sits to the immediate right of G" gives D = G + 1 = seat 1.
"Only two people sit between F and D, counted from the right of F" means D sits 2 + 1 = 3 seats to the right of F, so F = D − 3 = 1 − 3 = seat 5 (mod 7).
"Only three people sit between B and G, counted from the right of G" means B sits 3 + 1 = 4 seats to the right of G, so B = G + 4 = seat 4.
Seats 2, 3 and 6 remain unassigned, for A, C and E.
"E sits to the immediate right of A" means E = A + 1. Testing the free seats: A = 2 gives E = 3 (both still free — valid); A = 3 gives E = 4, already held by B; A = 6 gives E = 0, already held by G. So A = seat 2 and E = seat 3.
Only seat 6 is left over, so C = seat 6.
Counting rightward from E (seat 3): the next seat is B (4), then F (5), then C (6) — so two people, B and F, sit between E and C.
Seat | Occupant |
|---|---|
0 | G |
1 | D |
2 | A |
3 | E |
4 | B |
5 | F |
6 | C |
Cross-check
Reading the first clue against this seating: from F (seat 5) moving right, the seats passed before reaching D (seat 1) are C (6) and G (0) — exactly two people, matching "only two people between F and D."
Reading the second clue against this seating: from G (seat 0) moving right, the seats passed before reaching B (seat 4) are D (1), A (2) and E (3) — exactly three people, matching "only three people between B and G."
Both original clues hold against this same seating, so the arrangement is consistent. Exactly two people — B and F — sit between C and E when counted from the right of E.