The table given below shows the distribution percentage of number of…
2023
The table given below shows the distribution percentage of number of candidates qualifying a Common Entrance Test (CET) in six cities A-F during the year 2020 and 2021, along with the ratio of males (M) to females (F) among the qualified candidates. The total number of qualified candidates in all the six cities together during 2020 and 2021 are 3800 and 4600 respectively. Based on the data in the table, answer the question that follows:
City-wise Distribution of CET Qualified Candidates.
Years | 2020 | 2021 | ||
|---|---|---|---|---|
City | Distribution % of Qualified Candidates | Ratio M:F | Distribution % of Qualified Candidates | Ratio M:F |
A | 13% | 8:5 | 24% | 5:7 |
B | 27% | 11:8 | 15% | 12:11 |
C | 11% | 7:4 | 23% | 15:8 |
D | 20% | 2:3 | 17% | 8:9 |
E | 8% | 5:3 | 8% | 1:3 |
F | 21% | 13:8 | 13% | 5:8 |
The number of females qualified from City-F in 2020 is ____% of the number of candidates qualified from City-E in the same year.
Answer: D. 100 — CONCEPT: To convert a distribution percentage into a count, multiply the total by the percentage divided by 100. When a group is divided in the ratio M:F, the…
- A.
60
- B.
75
- C.
80
- D.
100
Show answer & explanation
Correct answer: D
CONCEPT: To convert a distribution percentage into a count, multiply the total by the percentage divided by 100.
When a group is divided in the ratio M:F, the female share is F/(M+F). To express one count as a percentage of another, use (first count/second count) × 100.
APPLICATION
City F candidates in 2020 = (21/100) × 3800 = 798.
Females in City F = [8/(13 + 8)] × 798 = (8/21) × 798 = 304.
City E candidates in 2020 = (8/100) × 3800 = 304.
Required percentage = (304/304) × 100 = 100%.
CROSS-CHECK: City F contributes 21% of the total, and females form 8/21 of that city total. The factors 21 and 1/21 cancel, leaving 8% of 3800—the same count as City E's 8% share.
Result: 100%