Match the column: Square of opposition Result a. if ‘A’ is true i. ‘A’ is…

2024

Match the column:

Square of opposition

Result

a. if ‘A’ is true

i. ‘A’ is undetermined; ‘I’ is true

b. if ‘E’ is false

ii. ‘E’ is false, ‘A’ is true

c. if ‘I’ is true

iii. ‘I’ is true, ‘E’ is false

d. if ‘O’ is false

iv. ‘O’ is undetermined, ‘E’ is false

Answer: D. a-iii b-i c-iv d-iiConceptThe traditional (Aristotelian) square of opposition arranges the four categorical propositions: A, the universal affirmative (“All S are P”); E, the…

  1. A.

    a-i b-ii c-iii d-iv

  2. B.

    a-iv b-i c-ii d-iii

  3. C.

    a-iv b-iii c-ii d-i

  4. D.

    a-iii b-i c-iv d-ii

Show answer & explanation

Correct answer: D

Concept

The traditional (Aristotelian) square of opposition arranges the four categorical propositions: A, the universal affirmative (“All S are P”); E, the universal negative (“No S is P”); I, the particular affirmative (“Some S are P”); and O, the particular negative (“Some S are not P”).

Four relations hold between them. Contradictories — A with O, and E with I — always take opposite truth values, so each one fixes the other completely. Contraries — A with E — cannot both be true, although both may be false. Subcontraries — I with O — cannot both be false, although both may be true. Subalternation runs A → I and E → O: truth descends from a universal to its particular, and falsity ascends from a particular to its universal.

Anything these relations do not settle is left undetermined; that is the whole content of a match-the-column item built on the square.

Application

Feed each given truth-value into the relations and read off what follows:

  1. ‘A’ is true. Its contradictory ‘O’ turns false; its contrary ‘E’ must be false, because two contraries cannot both be true; and subalternation carries the truth down to ‘I’. Every corner is settled, and the pair recorded in the Result column is “‘I’ is true, ‘E’ is false” — entry iii.

  2. ‘E’ is false. Its contradictory ‘I’ turns true. ‘A’ is not settled: a false ‘E’ only rules out A and E being true together, and both “All S are P” (A true) and “Some but not all S are P” (A false) make ‘E’ false. The pair recorded is “‘A’ is undetermined; ‘I’ is true” — entry i.

  3. ‘I’ is true. Its contradictory ‘E’ turns false. ‘O’ is not settled: subcontraries only forbid both being false, so ‘O’ may be either true or false while ‘I’ is true. The pair recorded is “‘O’ is undetermined, ‘E’ is false” — entry iv.

  4. ‘O’ is false. Its contradictory ‘A’ turns true, and because subalternation gives E → O, a false ‘O’ forces ‘E’ false as well; ‘I’ then follows as true. The pair recorded is “‘E’ is false, ‘A’ is true” — entry ii.

Cross-check

Set the four rows side by side and confirm that every Result entry is consumed once:

Given

Forced by the square

Left undetermined

Result entry

‘A’ is true

‘E’ false, ‘I’ true, ‘O’ false

none

iii

‘E’ is false

‘I’ true

‘A’, ‘O’

i

‘I’ is true

‘E’ false

‘A’, ‘O’

iv

‘O’ is false

‘A’ true, ‘I’ true, ‘E’ false

none

ii

Entries i, ii, iii and iv are each consumed once, so the matching is one-to-one. The two “undetermined” verdicts land exactly where the square leaves slack — a false universal negative and a true particular affirmative each fix only their contradictory — while the two stronger inputs settle every corner. The match is therefore a–iii, b–i, c–iv, d–ii.

Explore the full course: Nta Ugc Net Paper 1

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