Direction : Read the given information carefully and answer the given…
2021
Direction : Read the given information carefully and answer the given questions based on it.:
Seven persons S, E, V, B, A, D and U sit in a row facing north and they all work in a company with different working experience of 15yr, 7yr, 2yr, 23yr, 19yr, 6yr and 12yr. All the information is not necessarily in the same order as given. The persons with vowel name have experience of even number year and neither sits at the end nor at exactly middle of the row. Three persons sit between S and the one having 23yr experience. One person sits between S and A. The number of persons sits to the right of A is same as the number of persons sits to the left of the one having experience 2.5 times of A. B neither have highest year experience nor sits adjacent to S. The person having least experience sits second to the left of D. U does not have least experience. The neighbors of B have more experience than B.
Which among the following is correct combination?
- A.
E-12
- B.
V-19
- C.
A-2
- D.
U-12
- E.
D-23
Attempted by 3 students.
Show answer & explanation
Correct answer: D
Concept
In a linear seating-with-attribute puzzle, you fix positions by anchoring on the most constrained clue first (a fixed gap), then propagate each remaining clue as a filter, and finally attach the numeric attribute (experience) using the parity and position rules. A vowel-named person here must have an even experience and may occupy only the inner non-central seats.
Setting up
Seven seats face north, numbered 1 to 7 from left to right (seat 4 is the exact middle). The available experiences are 23, 19, 15, 12, 7, 6 and 2 years; the even values are 2, 6 and 12, so each vowel name (E, A, U) must take one of these and must sit in seat 2, 3, 5 or 6 (not the ends 1 or 7, not the centre 4).
Deduction
Three people sit between S and the 23-year person, so they are 4 seats apart. Combined with "one person between S and A" (2 seats apart), the only consistent fit places the 23-year person at seat 1, A at seat 3 and S at seat 5.
The count to the right of A equals the count to the left of the person whose experience is 2.5 times A's. A is at seat 3, so 4 people sit to its right; the 2.5-times person must therefore have 4 people to the left, i.e. sit at seat 5 (which is S). So A multiplied by 2.5 equals S's experience, and the even options for A give A = 6 and S = 15.
The least-experienced (2-year) person sits second to the left of D. Testing the open seats, D fits at seat 4 with the 2-year person at seat 2; that seat-2 person is the vowel E (even value, inner seat), so E = 2.
B cannot have the highest experience and cannot sit next to S, so B's only valid seat is the end seat 7, and its single neighbour must have more experience than B. The people left for seats 1, 6 and 7 are V, U and B, with experiences 23, 19, 12 and 7 still to place.
U is a vowel, so it must sit at the inner seat 6 (seats 1 and 7 are ends) and carry an even experience. The only even value left is 12, so U = 12. That leaves V at seat 1 with 23 and B at seat 7 with the smallest remaining value, 7; B's only neighbour U (12) indeed has more experience, and D takes 19.
Final arrangement
Seat (left to right) | Person | Experience (yr) |
|---|---|---|
1 | V | 23 |
2 | E | 2 |
3 | A | 6 |
4 | D | 19 |
5 | S | 15 |
6 | U | 12 |
7 | B | 7 |
Cross-check
Every clue holds: V (23) and S are 4 seats apart with three people between them; S and A have one person between; A's right side has 4 people, matching the left side of S, whose 15 equals 2.5 times 6; E (2) is two seats left of D; B at the end has its only neighbour U (12) above its own 7 and is not next to S; all vowels (E, A, U) carry even values on inner non-central seats. The combination that matches this arrangement is U with 12 years.