Direction : Read the given information carefully and answer the given…
2021
Direction : Read the given information carefully and answer the given questions based on it.:
Seven persons S, E, V, B, A, D and U sit in a row facing north and they all work in a company with different working experience of 15yr, 7yr, 2yr, 23yr, 19yr, 6yr and 12yr. All the information is not necessarily in the same order as given. The persons with vowel name have experience of even number year and neither sits at the end nor at exactly middle of the row. Three persons sit between S and the one having 23yr experience. One person sits between S and A. The number of persons sits to the right of A is same as the number of persons sits to the left of the one having experience 2.5 times of A. B neither have highest year experience nor sits adjacent to S. The person having least experience sits second to the left of D. U does not have least experience. The neighbors of B have more experience than B.
How many persons sit to the right of the one having 1yr less experience than B?
- A.
Five
- B.
Three
- C.
Four
- D.
One
- E.
None of these
Attempted by 4 students.
Show answer & explanation
Correct answer: C
Concept
In a linear (single-row) seating puzzle, you fix positions and attributes by chaining definite clues. Three lever rules carry this set: a clue of the form “N persons sit between X and Y” fixes the gap |posX − posY| = N+1; an attribute clue (here, vowel-named persons have even experience) partitions the values before you place anyone; and a “more/less than” neighbour clue tells you who can occupy an end versus the interior. Lock the most constrained value first, then propagate.
Setting up the values
Seven experiences are 15, 7, 2, 23, 19, 6 and 12 years. The only even values are 2, 6 and 12, and there are exactly three vowel-named persons (E, A, U), so the vowels take {2, 6, 12} and the consonant names (S, V, B, D) take {15, 7, 23, 19}.
“The number to the right of A equals the number to the left of the person whose experience is 2.5 × A’s.” A is a vowel, so A ∈ {2, 6, 12}. Testing: 2.5×2 = 5 (not a listed value), 2.5×6 = 15 (a listed value), 2.5×12 = 30 (not listed). Hence A = 6, and the reference person has 15 years.
U is not the least-experienced and U is a vowel, so U ∈ {6, 12}; since A = 6, we get U = 12, leaving E = 2 (E is therefore the least-experienced).
Placing the persons
Vowel-named persons (E, A, U) cannot sit at either end or in the exact middle, so they occupy only positions 2, 3, 5 or 6.
“Three persons sit between S and the 23-year person” → the gap is 4 seats. “One person sits between S and A” → the gap is 2 seats. Combined with A being restricted to positions {2, 3, 5, 6}, two mirror placements satisfy the right-equals-left count of step 1: either A at position 3 with the 15-year person (S) at position 5, or A at position 5 with S at position 3 (in both, the count to A’s right equals the count to the 15-year person’s left).
The mirror branch (A at position 5, S at position 3) forces the 23-year person to position 7 and, after placing E and D, leaves B at position 1 with the 2-year person as its only neighbour. But B’s neighbour must out-experience B, which is impossible against the lowest value, so this branch is rejected. Hence A is at position 3 and S at position 5.
The 23-year person sits four seats from S (position 5), i.e. at position 1; the least-experienced person E (2 years) sits “second to the left of D”, fixing E at position 2 and D at position 4.
B is neither the highest-experienced (not 23) nor adjacent to S, and B’s neighbour(s) must out-experience B. The remaining seat that satisfies all three is an end seat next to a high-experience person, giving B = 7 years.
Final order (left → right): V(23), E(2), A(6), D(19), S(15), U(12), B(7).
Answering the question
B has 7 years, so “one year less than B” is 6 years — that is A, seated at position 3. Counting everyone seated to A’s right gives the four persons at positions 4, 5, 6 and 7.
Cross-check
Vowels E, A, U hold even values 2, 6, 12 and sit only in the interior — consistent.
Right of A = left of the 15-year person: 4 = 4 — consistent.
E (least) is two seats left of D, and B’s only neighbour (12 years) exceeds B’s 7 — consistent.
Answer: Four.