Direction : Read the given information carefully and answer the given…
2021
Direction : Read the given information carefully and answer the given questions based on it.:
Seven persons S, E, V, B, A, D and U sit in a row facing north and they all work in a company with different working experience of 15yr, 7yr, 2yr, 23yr, 19yr, 6yr and 12yr. All the information is not necessarily in the same order as given. The persons with vowel name have experience of even number year and neither sits at the end nor at exactly middle of the row. Three persons sit between S and the one having 23yr experience. One person sits between S and A. The number of persons sits to the right of A is same as the number of persons sits to the left of the one having experience 2.5 times of A. B neither have highest year experience nor sits adjacent to S. The person having least experience sits second to the left of D. U does not have least experience. The neighbors of B have more experience than B.
What is the experience of V?
- A.
23yr
- B.
19yr
- C.
15yr
- D.
7yr
- E.
Either 19yr or 7yr
Attempted by 3 students.
Show answer & explanation
Correct answer: A
Concept
A linear seating puzzle is cracked by turning every clue into a hard positional or value constraint, fixing the strongest anchor clues first, then eliminating impossibilities. Two rules govern this set: a vowel-named person (E, A, U) must hold an even number of years and may sit only in seats 2, 3, 5 or 6 (never an end, never the exact middle); and "k persons sit between X and Y" fixes the gap |posX - posY| = k + 1.
Applying the clues
Even experiences are 2, 6, 12; odd are 15, 7, 23, 19. The three vowel names E, A, U therefore take 2, 6 and 12 in some order, each restricted to seat 2, 3, 5 or 6.
"Three persons sit between S and the 23-year person" means |posS − pos(23)| = 4. "One person sits between S and A" means |posS − posA| = 2.
"People to the right of A = people to the left of the 2.5×A-year person." Since 2.5×A must be a listed value, A = 6 forces 2.5×6 = 15. With A in seat 3, four people sit to its right, so the 15-year person needs four people to the left — seat 5 — and |posS − posA| = 2 then puts S in seat 5. Hence S holds 15 years.
With S at seat 5, the 23-year person sits at seat 1. The 2-year (least) person sits two seats to the left of D, and U is not the least, so E = 2 in seat 2 and D in seat 4. D in the exact middle cannot be a vowel value, so D = 19.
B is not the highest (B ≠ 23), is not adjacent to S, and its only neighbour must out-experience it. Seats 6 and 7 remain for U and B: U = 12 in seat 6 and B = 7 in seat 7, whose lone neighbour 12 exceeds 7. The single empty seat, seat 1, must be V.
Cross-check
Final order, left to right: V(23), E(2), A(6), D(19), S(15), U(12), B(7). Vowels E, A, U hold even years in seats 2, 3, 6 — none at an end or the middle; three people sit between V and S; one between S and A; right of A = left of S = 4; B's only neighbour (12) beats B(7); E(2) is two seats left of D. All clues hold, so the seating is unique.
Result
V sits at the far-left end, with 23 years of experience.