The table given below shows the total number of wooden and mechanical pencils…

Concept: When a fixed quantity of two item-types together has a known total count and a known total cost, the split is found by solving two linear equations. If w wooden and m mechanical pencils satisfy w + m = total and 5w + 20m = total price, subtract 5 times the first equation from the second to get 15m = (total price) - 5*(total), which isolates the mechanical count. To express one number as a percentage of another, divide it by the other and multiply by 100.

Application - find wooden pencils of E and the mechanical pencils of F:

1. Shop E: total = 40, price = 425. So 15m = 425 - 5*40 = 425 - 200 = 225, giving mechanical m = 15 and wooden w = 40 - 15 = 25. Wooden pencils of E = 25.

2. Shop D (needed for F): total = 75, price = 900. So 15m = 900 - 5*75 = 900 - 375 = 525, giving mechanical = 35 and wooden = 75 - 35 = 40. Wooden pencils of D = 40.

3. Shop C total = 112, and (total of F):(total of C) = 5:7, so total of F = 112*(5/7) = 80.

4. Shop F has 30% more wooden pencils than D, so wooden of F = 40*1.30 = 52. Hence mechanical of F = total of F - wooden of F = 80 - 52 = 28.

5. Compare mechanical of F (= 28) with wooden of E (= 25): 28/25 = 1.12, i.e. 28 is 112% of 25 (equivalently, 28 is 12% more than 25). Matching the offered percentage values, the answer is 112%.

Cross-check: 112% of 25 = 1.12*25 = 28, which equals the mechanical pencils of F, confirming the comparison. Also verify the splits by cost: for E, 5*25 + 20*15 = 125 + 300 = 425 (matches the table price); for D, 5*40 + 20*35 = 200 + 700 = 900 (matches). The required value is 112%.