Directions : Read the following table carefully and answer the questions given…
2022
Directions : Read the following table carefully and answer the questions given below.
Table shows the percentage distribution of poems published out of total poems & stories published starting from 2011 to till 2013. Table also shows number of poems published starting from 2011 to till 2013.
Note: (a) Y+X=115
(b) Z=Y-X
(c) Y+Z=95
If number of poems published in 2015 was ‘7X+9’, then number of poems published in 2015 is what percentage more than the number of poems published in 2013?
- A.
3X/9 + 4
- B.
0.4Y − (0.2Z + 3)
- C.
Y/4 + Z/5
- D.
None of these
- E.
Both (b) & (a)
Show answer & explanation
Correct answer: B
Concept
In a data-interpretation table where the count column is cumulative (“till” a year), the count for a single year equals that year’s cumulative total minus the previous year’s cumulative total. A “what percentage more” comparison is then (new − base) ÷ base × 100, taken on the base (here, the earlier year’s single-year count).
Solve the variables from the notes
Y + X = 115 and Y + Z = 95, so subtracting gives X − Z = 20.
Z = Y − X, so Y = X + Z; substitute into Y + X = 115 to get 2X + Z = 115.
From X − Z = 20 we get Z = X − 20; then 2X + (X − 20) = 115 ⇒ 3X = 135 ⇒ X = 45.
Hence Z = 25 and Y = 70.
Find the single-year counts
The number column is cumulative: 702 by 2011, 1640 till 2012, 1910 till 2013. So poems published in 2013 = 1910 − 1640 = 270.
Poems published in 2015 = 7X + 9 = 7×45 + 9 = 324.
Percentage more
(324 − 270) ÷ 270 × 100 = 54 ÷ 270 × 100 = 20%.
Cross-check against the offered expressions
Evaluating each offered expression at X = 45, Y = 70, Z = 25 shows that 0.4Y − (0.2Z + 3) = 28 − 8 = 20 matches the computed 20%, while 3X/9 + 4 = 19 and Y/4 + Z/5 = 22.5 do not.