A two-way switch has three terminals a, b and c. In ON position (logic value…

2005

A two-way switch has three terminals a, b and c. In ON position (logic value 1), a is connected to b, and in OFF position, a is connected to c. Two of these two-way switches S1 and S2 are connected to a bulb as shown below.

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Which of the following expressions, if true, will always result in the lighting of the bulb ?

  1. A.

    S1.S2'

  2. B.

    S1+S2

  3. C.

    (S1⊕S2)'

  4. D.

    S1⊕S2

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Correct answer: C

Answer: (S1⊕S2)' (exclusive OR)
To keep the bulb ON, both switches must complete the circuit through the same path.
That means:

  • If S1 is in position a–b, then S2 must also be in the same position.

  • If S1 is in position c–d, then S2 must also match that position.

So the bulb glows only when both inputs are the same.

This behavior matches the EX-NOR gate, because:

  • For same inputs (0-0 or 1-1), EX-NOR output = 1 → bulb ON

  • For different inputs, EX-NOR output = 0 → bulb OFF

Thus the correct Boolean expression is:

(S1⊕S2)EX-NOR gives 1 when inputs are equal — exactly what the circuit requires.

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