Sachin walks 20 km towards North. He turns left and walks 40 km. He again…

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Sachin walks 20 km towards North. He turns left and walks 40 km. He again turns left and walks 20 km. Finally he moves 20 km after turning to the left. How far is he from his starting position?

  1. A.

    20 km

  2. B.

    30 km

  3. C.

    50 km

  4. D.

    60 km

Attempted by 9 students.

Show answer & explanation

Correct answer: A

Step-by-Step Solution

To find how far Sachin is from his starting position, we need to track his net displacement by breaking his journey into vertical (North-South) and horizontal (East-West) movements.

  1. Trace the movements:

    • Start at origin (0, 0).

    • Move 20 km North: Position is (0, 20).

    • Turn left (West) and move 40 km: Position is (-40, 20).

    • Turn left (South) and move 20 km: Position is (-40, 0).

    • Turn left (East) and move 20 km: Position is (-40 + 20, 0) = (-20, 0).

  2. Calculate net displacement:

    • His final position is 20 km West of his starting position.

    • The distance from the starting position is the magnitude of the displacement, which is 20 km.

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