The width of the physical address on a machine is 32 bits, 4 way set…
The width of the physical address on a machine is 32 bits, 4 way set associative cache each block hold 1kilo byte and having word of size 4 bytes. There are 512 blocks in the cache. Initially cache is empty then how many data words are brought into the cache ______________ (In Kwords) ?
Answer: 128 — Block size = 1024 bytes Word size = 4 bytes Number of words per block = Block size / Word size = 1024 bytes / 4 bytes = 256 words. Total data words = 256…
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Correct answer: 128
Block size = 1024 bytes
Word size = 4 bytes
Number of words per block = Block size / Word size = 1024 bytes / 4 bytes = 256 words.
Total data words = 256 words/block x 512 blocks = 128 KWords
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