Suppose a CSMA/CD local Area Network of 1 Gbps is there over a 1 km cable. If…
2018
Suppose a CSMA/CD local Area Network of 1 Gbps is there over a 1 km cable. If the signal speed in the cable is 2 x 105 km/sec, what will be the minimum frame size?
- A.
4000
- B.
100000
- C.
10000
- D.
5000
Attempted by 104 students.
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Correct answer: C
The minimum frame size for CSMA/CD is calculated as Bandwidth multiplied by the Round-Trip Propagation Delay.
First, find propagation delay: distance divided by speed equals 1 km / (2 x 10^5 km/s) = 5 microseconds.
Round-trip time is double the one-way delay, resulting in 10 microseconds.
Multiplying this by the bandwidth of 1 Gbps yields exactly 10,000 bits.