An organization is granted the block 130.56.0.0/16. The administrator wants to…
2022
An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets.
Find first and last addresses of First subnet.
Answer: B. 130.56.0.0 130.56.0.63 — Solution: Steps to find the first subnet range when splitting 130.56.0.0/16 into 1024 subnets. Start with the given network: 130.56.0.0/16. Number of subnets…
- A.
130.56.0.0 130.56.254.254
- B.
130.56.0.0 130.56.0.63
- C.
130.0.0.0 130.255.255.255
- D.
130.56.0.0 130.56.255.63
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Correct answer: B
Solution: Steps to find the first subnet range when splitting 130.56.0.0/16 into 1024 subnets.
Start with the given network: 130.56.0.0/16.
Number of subnets required: 1024 = 2^10, so you must borrow 10 bits from the host portion.
New prefix length: 16 + 10 = /26.
Addresses per subnet: 2^(32 - 26) = 64 addresses (values 0–63 in the fourth octet).
First subnet range: network address 130.56.0.0 to broadcast address 130.56.0.63.
Usable host addresses in the first subnet: 130.56.0.1 through 130.56.0.62.
Answer: First subnet = 130.56.0.0 — 130.56.0.63 (usable hosts 130.56.0.1–130.56.0.62).
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