An organization is granted the block 130.56.0.0/16. The administrator wants to…

Key idea: determine how many additional bits are needed to create 1024 subnets from a /16 network.

1. Step 1: Calculate bits needed for 1024 subnets: 1024 = 2^10, so 10 bits are required.

2. Step 2: Add those bits to the original prefix: 16 + 10 = 26, so the new subnet prefix is /26.

3. Step 3: Determine the subnet mask: /26 corresponds to 255.255.255.192.

4. Step 4: Compute addresses per subnet: 2^(32-26) = 64 addresses per subnet (62 usable hosts when excluding network and broadcast).

5. Step 5: Example subnets within 130.56.0.0/16: 130.56.0.0/26, 130.56.0.64/26, 130.56.0.128/26, 130.56.0.192/26, then 130.56.1.0/26, etc.

Final answer: The subnet prefix is /26 (so the block 130.56.0.0/16 can be divided into 1024 subnets of size 130.56.x.x/26, with mask 255.255.255.192).