Ten signals, each requiring 3000 Hz, are multiplexed on to a single channel…
2014
Ten signals, each requiring 3000 Hz, are multiplexed on to a single channel using FDM. How much minimum bandwidth is required for the multiplexed channel ? Assume that the guard bands are 300 Hz wide.
- A.
30,000
- B.
32,700
- C.
33,000
- D.
None of the above
Attempted by 267 students.
Show answer & explanation
Correct answer: B
Step 1: Formula — For FDM, total bandwidth = (number of signals × bandwidth per signal) + (number of guard bands × guard band width).
Number of signals (N): 10
Bandwidth per signal (W): 3000 Hz
Guard band width (G): 300 Hz
Number of guard bands = N − 1 = 9
Step 2: Compute contributions
Total signal bandwidth = 10 × 3000 = 30,000 Hz
Total guard-band bandwidth = 9 × 300 = 2,700 Hz
Step 3: Add them
Total minimum bandwidth required = 30,000 + 2,700 = 32,700 Hz
Therefore the minimum bandwidth required for the multiplexed channel is 32,700 Hz.
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