Four channels are multiplexed using TDM. If each channel sends 100…
2015
Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is
- A.
400 bps
- B.
800 bps
- C.
1600 bps
- D.
3200 bps
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Correct answer: D
Explanation: compute frames per second and convert bytes to bits.
Each channel sends 100 bytes per second.
Multiplexing 1 byte per channel means each frame carries 4 bytes (one byte from each of the four channels).
Frames needed per second = 100 bytes/s per channel ÷ 1 byte per channel per frame = 100 frames/s.
Total bytes transmitted per second = 4 bytes/frame × 100 frames/s = 400 bytes/s.
Convert to bits: 400 bytes/s × 8 = 3200 bits/s.
Answer: 3200 bps