The following table displays the percentage of marks obtained by six different…
2023
The following table displays the percentage of marks obtained by six different students in six different subjects A-F of the MCA program in a university, and the maximum marks for each subject are given along with it (shown in brackets).
Student | A(150) | B(100) | C(150) | D(125) | E(75) | F(50) |
Anil | 66% | 75% | 88% | 56% | 56% | 90% |
Arman | 82% | 76% | 84% | 96% | 92% | 88% |
Arpit | 76% | 66% | 78% | 88% | 72% | 70% |
Gaurav | 90% | 88% | 96% | 76% | 84% | 86% |
Gurjeet | 64% | 70% | 68% | 72% | 68% | 74% |
Priya | 48% | 56% | 50% | 64% | 64% | 58% |
If M and N represent the averages of marks obtained by all six students in subjects C and E respectively, then (M, N) = ?
Answer: D. (116, 54.5) — First, determine actual marks in Subject C by multiplying each student's percentage by the maximum of 150. The total sum is 696, so dividing by six students…
- A.
(112, 56.5)
- B.
(114, 55)
- C.
(115, 56)
- D.
(116, 54.5)
Attempted by 4 students.
Show answer & explanation
Correct answer: D
First, determine actual marks in Subject C by multiplying each student's percentage by the maximum of 150. The total sum is 696, so dividing by six students gives the average M as 116.
Then, calculate marks for Subject E using the maximum of 75. The sum totals 327, which divided by six students results in the average N equaling 54.5.