The following table displays the percentage of marks obtained by six different…
2023
The following table displays the percentage of marks obtained by six different students in six different subjects A-F of the MCA program in a university, and the maximum marks for each subject are given along with it (shown in brackets).
Student | A(150) | B(100) | C(150) | D(125) | E(75) | F(50) |
Anil | 66% | 75% | 88% | 56% | 56% | 90% |
Arman | 82% | 76% | 84% | 96% | 92% | 88% |
Arpit | 76% | 66% | 78% | 88% | 72% | 70% |
Gaurav | 90% | 88% | 96% | 76% | 84% | 86% |
Gurjeet | 64% | 70% | 68% | 72% | 68% | 74% |
Priya | 48% | 56% | 50% | 64% | 64% | 58% |
By what percent are the total marks obtained by Gaurav more than the total marks obtained by Gurjeet across all six subjects? (Rounded to two decimal places)
Answer: A. 27.35 — First, calculate Gaurav's total marks by multiplying his percentages by the maximum marks for each subject: (150×90% + 100×88% + 150×96% + 125×76% + 75×84% +…
- A.
27.35
- B.
24.52
- C.
29.45
- D.
28.15
Attempted by 2 students.
Show answer & explanation
Correct answer: A
First, calculate Gaurav's total marks by multiplying his percentages by the maximum marks for each subject: (150×90% + 100×88% + 150×96% + 125×76% + 75×84% + 50×86%) = 568.
Next, calculate Gurjeet's total marks similarly: (150×64% + 100×70% + 150×68% + 125×72% + 75×68% + 50×74%) = 446.
Finally, find the percentage increase: ((568 - 446) / 446) × 100 ≈ 27.35%.