Select the pair that follows the same pattern as that followed by the two…
2025
Select the pair that follows the same pattern as that followed by the two pairs given below. Both pairs follow the same pattern.
KNR-UXB NQU-XAE
Answer: D. VYC-FIM — ConceptOn the cyclic alphabet every letter carries a position — A = 1, B = 2, … Z = 26 — and a count that passes 26 wraps back to A. A pair of letter groups…
- A.
VXA-EHL
- B.
VYC-EIL
- C.
VXA-FIM
- D.
VYC-FIM
Attempted by 1 students.
Show answer & explanation
Correct answer: D
Concept
On the cyclic alphabet every letter carries a position — A = 1, B = 2, … Z = 26 — and a count that passes 26 wraps back to A. A pair of letter groups is then fixed by two independent quantities: the inner gaps between consecutive letters within a group, and the positional shift that carries each letter of the first group to the letter standing in the same place in the second group.
A candidate reproduces the pattern only when BOTH quantities repeat the values the given pairs establish — matching one of them is not enough.
Applying the concept to the two given pairs
Given pair | Inner gaps | Group-to-group shift |
|---|---|---|
KNR – UXB | +3, +4 in each group | +10 on every letter |
NQU – XAE | +3, +4 in each group | +10 on every letter |
First group of the first pair: K = 11, N = 14, R = 18, so the inner gaps are 14 − 11 = +3 and 18 − 14 = +4.
Second group of the first pair: U = 21, X = 24, B = 2; since 24 + 4 = 28 wraps to 2, its inner gaps are again +3 and +4.
Compare the two groups letter by letter: 11 + 10 = 21 (K → U), 14 + 10 = 24 (N → X), 18 + 10 = 28 → 2 (R → B). The shift is a constant +10.
Repeat on the second pair: N = 14, Q = 17, U = 21 give gaps +3 and +4; X = 24, A = 1, E = 5 give 24 + 3 = 27 → 1 and 27 + 4 = 31 → 5, so gaps +3 and +4 again.
Its shift: 14 + 10 = 24 (N → X), 17 + 10 = 27 → 1 (Q → A), 21 + 10 = 31 → 5 (U → E) — a constant +10 once more.
So the required pair must show inner gaps of +3 and +4 in both groups and a constant +10 between them.
Build it from V = 22: 22 + 3 = 25 = Y and 25 + 4 = 29 → 3 = C, giving the first group VYC.
Now add 10 to each of its letters: 22 + 10 = 32 → 6 = F, 25 + 10 = 35 → 9 = I, 3 + 10 = 13 = M, giving the second group FIM.
Cross-check against the other candidate values
VXA – EHL: inside VXA the gaps are +2 and +3, and the group-to-group shifts read +9, +10, +11, so neither quantity is constant.
VYC – EIL: inside EIL the gaps run +4 then +3 rather than +3 then +4, and the shifts read +9, +10, +9.
VXA – FIM: inside VXA the gaps are +2 and +3, and the shifts read +10, +11, +12.
Both requirements — inner gaps of +3 and +4 in each group and a constant +10 between the groups — hold together only for VYC – FIM.