Select the pair that follows the same pattern as that followed by the two…

Concept — how a letter-group analogy is fixed. Two independent rules decide such an analogy. The first is the internal shape of a group: the gaps between the alphabet positions of its letters, written in the form (X, X + k, …). The second is the step that carries the first group onto the second, applied letter by letter at matching places; that step counts only when it is the same at every place. A candidate reproduces the analogy only when both rules hold exactly.

Applying it to the given pairs.

1. Take HLH and write the alphabet positions: H = 8, L = 12, H = 8. The second letter stands 4 places after the first and the third repeats the first, so the shape is (X, X + 4, X) with X = 8.

2. Take JNJ: J = 10, N = 14, J = 10. The same shape (X, X + 4, X) appears, now with X = 10.

3. Compare the two groups place by place: H → J, L → N, H → J. Each letter moves forward by 2, so the step is a uniform +2.

4. Repeat on the second given pair. AEA: A = 1, E = 5, A = 1, again (X, X + 4, X). CGC: C = 3, G = 7, C = 3, again (X, X + 4, X). Place by place A → C, E → G, A → C, again a uniform +2.

5. So the signature to reproduce is: both groups carry the shape (X, X + 4, X), and the second group is the first group moved forward by exactly 2 at every place.

Cross-check against every offered pair.

Result. Only MQM-OSO satisfies both rules at once: each of its groups carries the shape (X, X + 4, X), and the second group is the first moved forward by 2 at every place. Reading it back, M + 4 = Q with the third letter repeating M, then M + 2 = O, Q + 2 = S and M + 2 = O — precisely the relation seen in HLH-JNJ and in AEA-CGC. The pair that follows the same pattern is therefore MQM-OSO.