Seven boxes, A, B, C, D, K, L and M, are kept one over the other, but not…

Concept

In a linear floor/box-stacking arrangement, first place any element that has an absolute-position clue (a stated count of items below or above it fixes that element's slot from one end). Once such anchors are fixed, apply the relative-order clues (immediately above/below, a stated gap between two elements) to lock the remaining slots, and use any leftover inequality clue (one element below another) only to break ties among the slots that are still open.

Application

1. Number the seven slots 1 (bottom-most) to 7 (top-most). The clue about K's position states that two boxes are kept below K, so K takes slot 3 (slots 1 and 2 lie below it).

2. The clue about L's position states that one box is kept above L, so L takes slot 6 (only slot 7 lies above it).

3. The clue about the gap next to L and D states that one box is kept between L and D. With L fixed at slot 6, the only open slot that leaves exactly one box between it and L is slot 4, so D takes slot 4 and slot 5 becomes the single box between them.

4. B is kept immediately above M, so B's slot number is exactly one more than M's. The still-open slots are 1, 2, 5 and 7; the only pair among these that differs by exactly one is 1 and 2, so M takes slot 1 and B takes slot 2.

5. Slots 5 and 7 remain for A and C. C is kept at some place below A, meaning C's slot number is smaller, so C takes slot 5 and A takes slot 7.

6. The complete bottom-to-top order is M, B, K, D, C, L, A.

Cross-check

Checking every clue against this order: two boxes (M, B) lie below K (slot 3); one box (A) lies above L (slot 6); exactly one box (C) lies between L and D; B sits immediately above M; and C sits below A. All five clues hold. Counting the boxes strictly between B (slot 2) and A (slot 7) covers slots 3 to 6 — K, D, C and L — so four boxes are kept between A and B.