Based on the English alphabetical order, three of the following four…

2026

Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which is the one that does not belong to that group?

(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)

Answer: C. ML - JIConceptAssign each English letter its alphabetical position: A = 1, B = 2, ..., Z = 26. For each pair of letter clusters, compare corresponding letters from…

  1. A.

    HG - FE

  2. B.

    WV - UT

  3. C.

    ML - JI

  4. D.

    SR - QP

Attempted by 50 students.

Show answer & explanation

Correct answer: C

Concept

Assign each English letter its alphabetical position: A = 1, B = 2, ..., Z = 26.

For each pair of letter clusters, compare corresponding letters from the first cluster with those in the second. Pairs in the same group use the same positional displacement; the odd pair uses a different displacement.

Application

  1. For HG - FE, H(8) → F(6) and G(7) → E(5); both positions decrease by 2.

  2. For WV - UT, W(23) → U(21) and V(22) → T(20); both positions decrease by 2.

  3. For ML - JI, M(13) → J(10) and L(12) → I(9); both positions decrease by 3.

  4. For SR - QP, S(19) → Q(17) and R(18) → P(16); both positions decrease by 2.

Cross-check

Reversing the rule confirms the grouping: moving each letter of FE, UT, and QP forward by 2 gives HG, WV, and SR, whereas JI must be moved forward by 3 to give ML.

Therefore, ML - JI does not belong to the group.

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