If 2 is added to each odd digit and 1 is subtracted from each even digit in…

2026

If 2 is added to each odd digit and 1 is subtracted from each even digit in the number 2561473, then how many digits will appear more than once in the new number thus formed?

  1. A.

    1

  2. B.

    2

  3. C.

    3

  4. D.

    None

Attempted by 49 students.

Show answer & explanation

Correct answer: B

Step 1: Write down the original number and the conditions.
Original number: 2561473
Conditions: Add 2 to odd digits, subtract 1 from even digits.

Step 2: Apply the conditions to each digit individually.

2 (Even) - 1 = 1

5 (Odd) + 2 = 7

6 (Even) - 1 = 5

1 (Odd) + 2 = 3

4 (Even) - 1 = 3

7 (Odd) + 2 = 9

3 (Odd) + 2 = 5
The new sequence is: 1753395

Step 3: Count the distinct digits that appear more than once.
In the sequence (1, 7, 5, 3, 3, 9, 5):

The digit 3 appears twice.

The digit 5 appears twice.
Thus, exactly two distinct digits appear more than once.

Final Answer: Option 2

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