What is the sum of the first 15 terms of the following series? 22,32,42,52,…

The series consists of squares starting from 2: 2^2, 3^2, ...

The 15th term corresponds to 16^2. We calculate the sum of squares from 1 to 16 and subtract 1^2.

Using the formula n(n+1)(2n+1)/6 for n=16, the sum is (16 * 17 * 33) / 6 = 1496.

Subtracting the first term (1^2=1), the final sum is 1496 - 1 = 1495.