The present ages of three persons are in the proportion 4 : 5 : 7. Seven years…
2026
The present ages of three persons are in the proportion 4 : 5 : 7. Seven years ago, the sum of their ages was 59 years. The present age of youngest of them is:
- A.
15 years
- B.
20 years
- C.
25 years
- D.
35 years
Attempted by 20 students.
Show answer & explanation
Correct answer: B
Let the present ages of the three persons be 4x, 5x, and 7x respectively.
Seven years ago, their ages were (4x - 7), (5x - 7), and (7x - 7). The sum of their ages at that time was given as 59 years.
Setting up the equation: (4x - 7) + (5x - 7) + (7x - 7) = 59. Simplifying gives 16x - 21 = 59, so 16x = 80 and x = 5.
The present age of the youngest person is 4x = 4 * 5 = 20 years.