A couple has a son and a daughter. The age of the father is four times that of…

2022

A couple has a son and a daughter. The age of the father is four times that of the son and the age of the daughter is one-third of that of her mother. The wife is 6 years younger to her husband and the sister is 3 years older than her brother. The mother’s age is –

  1. A.

    42 years

  2. B.

    48 years

  3. C.

    54 years

  4. D.

    63 years

Attempted by 20 students.

Show answer & explanation

Correct answer: C

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Solution: Use algebra to find the ages.

  1. Let the son’s age be x.

  2. Father’s age = 4x, so mother’s age = 4x − 6 (wife is 6 years younger than husband).

  3. Daughter’s age = x + 3 (sister is 3 years older than brother).

  4. Given that daughter’s age = one-third of mother’s age, set up the equation x + 3 = (4x − 6)/3.

  5. Solve: multiply both sides by 3: 3x + 9 = 4x − 6 ⇒ bring terms together: 9 + 6 = 4x − 3x ⇒ x = 15.

  6. Mother’s age = 4x − 6 = 4×15 − 6 = 60 − 6 = 54 years.

Answer: 54 years.

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