A, B, C, D, E and F are sitting around a circular table facing the centre. B…
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A, B, C, D, E and F are sitting around a circular table facing the centre. B sits to the immediate right of D. C is an immediate neighbour of both F and A. E sits third to the right of A. A is an immediate neighbour of D. What is the position of F with respect to E?
Answer: B. Immediate right — When people sit around a circular table facing the CENTRE, their own left and right are reversed compared to someone viewing the table from outside: a…
- A.
Third to the right
- B.
Immediate right
- C.
Immediate left
- D.
Second to the left
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Correct answer: B
When people sit around a circular table facing the CENTRE, their own left and right are reversed compared to someone viewing the table from outside: a person's immediate right is the seat one position anticlockwise (as seen from above), and their immediate left is one position clockwise. “nth to the right/left” simply repeats that same directional hop n times, starting from that person's own seat.
C is stated to be an immediate neighbour of both F and A, so C must sit directly between them: this fixes three consecutive seats as the block F–C–A.
A is also stated to be an immediate neighbour of D. A already has C as one neighbour, so D must be A's other neighbour, extending the block to four consecutive seats: D–A–C–F.
The four-person block has two possible mirror orientations. If the clockwise order were F–C–A–D, then D’s immediate-right seat (one place anticlockwise) would already be occupied by A, leaving no seat for B; that orientation is impossible. Therefore the clockwise order must be D–A–C–F. Place this block at seats 1–2–3–4: D at 1, A at 2, C at 3 and F at 4.
B sits to the immediate right of D. D occupies seat 1, and “immediate right” is one seat anticlockwise from seat 1, which is seat 6. So B takes seat 6, leaving seat 5 for E.
Independent check: E should sit third to the right of A. A is in seat 2; three seats anticlockwise from seat 2 (2 → 1 → 6 → 5) lands on seat 5, exactly where E was placed. This confirms the full seating order clockwise: D(1)–A(2)–C(3)–F(4)–E(5)–B(6).
F occupies seat 4 and E occupies seat 5. One seat anticlockwise from E's seat 5 is seat 4, F's seat. So F sits to the immediate right of E.
B sits to the immediate right of D: seat 6 (B) is one seat anticlockwise from seat 1 (D). Holds.
C is an immediate neighbour of both F and A: seat 3 (C) sits between seat 4 (F) and seat 2 (A). Holds.
E sits third to the right of A: seat 5 (E) is three seats anticlockwise from seat 2 (A). Holds.
A is an immediate neighbour of D: seat 2 (A) sits next to seat 1 (D). Holds.
All four conditions are satisfied, and the rejected mirror orientation proves that the seating order is unique. Therefore F sits to the immediate right of E.