A, B, C, D and E are seated around a circular table facing the centre. D is…

Concept: In a circular-seating problem where everyone faces the centre of the table, the clockwise direction around the table corresponds to each person's immediate LEFT, and the anticlockwise direction corresponds to each person's immediate RIGHT. This holds because, facing inward, a person's right hand points toward the seat one position anticlockwise from them, leaving the seat one position clockwise as their left-hand neighbour.

Application (deriving the seating order):

1. The clue "C is between B and E in clockwise direction" fixes three consecutive clockwise seats: B, then C, then E.

2. The clue "D is between A and E" means D's two neighbours are A and E. E already has one neighbour fixed as C from step 1, so E's other neighbour must be D, extending the clockwise run to: B, C, E, D.

3. D's remaining neighbour (other than E) must be A per the same clue, extending the run to: B, C, E, D, A.

4. With all five people placed, A's remaining neighbour must be B, closing the circle: clockwise order B -> C -> E -> D -> A -> B.

5. Applying the concept rule, the seat one position clockwise from B is B's immediate left neighbour: that seat is C.

Cross-check: Re-verify both clues against the completed order. "D is between A and E" holds, since A-D-E are consecutive. "C is between B and E in clockwise direction" holds, since B-C-E are consecutive in that clockwise order. As a second check, A sits immediately anticlockwise of B, so by the same rule A is B's immediate right neighbour -- consistent with B having exactly one left neighbour and one right neighbour in this five-seat circle.

Therefore, C is on the immediate left of B.