Which of the following statement is not True?

2025

Which of the following statement is not True?

Answer: C. The scope resolution operator (::) can be overloaded like normal operatorsCorrect answer: The scope resolution operator (::) can be overloaded like normal operators — this statement is not true. Why this is not true: The scope…

  1. A.

    A data member of a class can be declared as static and is normally used to maintain values common to the entire class.

  2. B.

    A friend function can be invoked like a normal function without the help of any object.

  3. C.

    The scope resolution operator (::) can be overloaded like normal operators

  4. D.

    Multiple inheritance may lead to duplication of inherited members from a “Grandparent” base class. This may be avoided by making the common base class a virtual base class.

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Correct answer: C

Correct answer: The scope resolution operator (::) can be overloaded like normal operators — this statement is not true.

Why this is not true:

  • The scope resolution operator (::) is a built-in language operator used for namespace and class scope resolution. C++ does not allow overloading of certain fundamental operators, including ::, because their behavior is intrinsic to language semantics.

  • Other examples of operators that cannot be overloaded include the member access operator (.), the pointer-to-member operator (.*), the conditional operator (?:), and sizeof. These are reserved by the language.

Brief confirmations of the other statements:

  • A data member declared static is shared by all instances of the class and is used to maintain values common to the class (for example, a class-level counter).

  • A friend function can be called like a normal (non-member) function without needing an object, but it is granted access to the class's private and protected members by the friend declaration.

  • Multiple inheritance can cause duplication of a common base class when it is inherited via multiple paths; declaring that common base as a virtual base class causes a single shared instance to be used, avoiding duplication.

Conclusion: The only incorrect statement is the one claiming the scope resolution operator can be overloaded; the other statements are correct for the reasons given above.

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