The following table shows the number of males (M) and females (F) (in…
2023
The following table shows the number of males (M) and females (F) (in thousands) in Towns X and Y during the five years from 2018 to 2022. Based on the data in the table:
Year wise numbers of Males and Females in two Towns (in thousands)
Year | Town X — number of males | Town X — number of females | Town Y — number of males | Town Y — number of females |
|---|---|---|---|---|
2018 | 50 | 49 | 53 | 50 |
2019 | 52 | 49 | 54 | 52 |
2020 | 55 | 52 | 55 | 54 |
2021 | 53 | 53 | 58 | 56 |
2022 | 55 | 52 | 62 | 55 |
The population of Town X in 2018 and 2019 together is approximately ______ % of the population of Town Y in 2021 and 2022 together?
Answer: A. 86.6 — ConceptTo compare one combined quantity with another as a percentage, first add all components for each requested group. Then use: percentage = (comparison…
- A.
86.6
- B.
89.6
- C.
81.6
- D.
84.5
Show answer & explanation
Correct answer: A
Concept
To compare one combined quantity with another as a percentage, first add all components for each requested group. Then use: percentage = (comparison quantity / reference quantity) × 100.
Application
Town X in 2018: 50 + 49 = 99 thousand.
Town X in 2019: 52 + 49 = 101 thousand.
Combined population of Town X for 2018 and 2019: 99 + 101 = 200 thousand.
Town Y in 2021: 58 + 56 = 114 thousand.
Town Y in 2022: 62 + 55 = 117 thousand.
Combined population of Town Y for 2021 and 2022: 114 + 117 = 231 thousand.
Required percentage = (200 / 231) × 100 ≈ 86.58%.
Cross-check
Using the rounded value, 86.6% of 231 is 0.866 × 231 ≈ 200.0 thousand, which reproduces the Town X total. Therefore, the required approximate percentage is 86.6%.