If UGCNET = 35, then CSIRNET = ?

CONCEPT

In letter-coding questions, each letter is first converted to its alphabet position: A=1, B=2, ..., Z=26.

The rule is inferred from the given example, and the identical rule must then be applied to the new word.

APPLICATION

1. For UGCNET, the letter positions are U=21, G=7, C=3, N=14, E=5, T=20.

2. The sum is 21 + 7 + 3 + 14 + 5 + 20 = 70, and 70 ÷ 2 = 35. So the rule is half of the position-sum.

3. For CSIRNET, the letter positions are C=3, S=19, I=9, R=18, N=14, E=5, T=20.

4. The sum is 3 + 19 + 9 + 18 + 14 + 5 + 20 = 88, and 88 ÷ 2 = 44.

CROSS-CHECK

Doubling the obtained value gives 88, which matches the position-sum of CSIRNET. Therefore, the required value is 44.