Read the information carefully and answer the questions given below: Seven…

2025

Read the information carefully and answer the questions given below:

Seven persons A, B, C, D, E, F and G were born on seven different years i.e., 1947, 1959, 1964, 1973, 1978, 1988 and 2001 on the same month and same date. (Base year is considered as 2025 for age calculation). The sum of the ages of C and F is equal to the age of D. G’s age is divisible by 6. The total age of A and G is a prime number. A is just older than F. The sum of the age of B and A is divisible by 5.

Who among the following was born on 1973?

  1. A.

    G

  2. B.

    B

  3. C.

    E

  4. D.

    A

  5. E.

    C

Show answer & explanation

Correct answer: C

Concept

In an age-based arrangement puzzle, first convert every birth year to an age using the stated base year (age = base year − birth year). Then translate each verbal clue (sum, divisibility, prime, "just older than") into an arithmetic condition on those ages, and eliminate year assignments until only one consistent mapping survives.

Step 1 — Convert birth years to ages (base year 2025)

Age = 2025 − birth year:

  • 1947 → 78, 1959 → 66, 1964 → 61

  • 1973 → 52, 1978 → 47, 1988 → 37, 2001 → 24

Step 2 — Apply the clues in the most restrictive order

  1. Sum of C and F equals D: scanning all pairs, the only two ages that add up to a third are 24 + 37 = 61. So {C, F} = {24, 37} and D = 61 (born 1964).

  2. A is just older than F: A's age is the next value above F's. F must be 24 or 37; if F = 24 the next age up is 37, which is already the other member of the C/F pair, so that fails. Hence F = 37 (born 1988), C = 24 (born 2001), and the next age up gives A = 47 (born 1978).

  3. G's age is divisible by 6: the ages divisible by 6 are 24, 66 and 78; since 24 is already taken by C, G is 66 or 78.

  4. A + G is prime: A = 47, so test the two candidates — 47 + 78 = 125 (= 5×25, not prime) but 47 + 66 = 113 (prime). Therefore G = 66 (born 1959).

  5. B + A is divisible by 5: A = 47, and the two ages still unassigned are 52 and 78. 47 + 78 = 125 is a multiple of 5 while 47 + 52 = 99 is not, so B = 78 (born 1947).

Step 3 — Final mapping

Only the age 52 is left, and it goes to E — so E was born in 1973.

Person

Age

Birth year

A

47

1978

B

78

1947

C

24

2001

D

61

1964

E

52

1973

F

37

1988

G

66

1959

Cross-check

C + F = 24 + 37 = 61 = D ✓; G = 66 is divisible by 6 ✓; A + G = 113 is prime ✓; B + A = 125 is divisible by 5 ✓. The person born in 1973 is E.

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