Read the given information carefully and answer the question that follows:…
2024
Read the given information carefully and answer the question that follows: Seven persons were born on the same date and same month but in different years - 1955, 1967, 1973, 1980, 1987, 1991, 2003. Consider the base year 2024 to calculate the ages. L's age is a multiple of 3. Three persons were born between L and Q. The number of persons born before Q is the same as the number of persons born after P. The difference between the ages of Q and K is 12 years. M is 7 years older than N. N is younger than O. M was born in which year?
- A.
1973
- B.
1980
- C.
1987
- D.
1967
- E.
1955
Show answer & explanation
Correct answer: B
Concept
In a 'born in different years' puzzle, arrange the people on a single timeline from oldest (earliest year) to youngest (latest year). Convert every age clue into a year clue using birth year = base year - age, and read 'older' as an earlier year and 'younger' as a later year. Apply the clues together, eliminating placements that violate any one of them, until a single arrangement survives.
Setting up
Years available: 1955, 1967, 1973, 1980, 1987, 1991, 2003. With base year 2024 the ages are 69, 57, 51, 44, 37, 33 and 21 respectively. We fill seven slots from oldest to youngest.
Applying the clues
L's age is a multiple of 3. Of the ages 69, 57, 51, 44, 37, 33, 21, the multiples of 3 are 69, 57, 51, 33 and 21 - so L is one of 1955, 1967, 1973, 1991 or 2003 (only 1980 and 1987 are excluded for L).
Three persons are born between L and Q, so L and Q sit four slots apart on the timeline. Combined with the next clues this fixes L = 1973 and Q = 2003: the four-slot span 1973 ... 2003 leaves exactly three people in between, and the other multiple-of-3 choices for L cannot keep all later clues consistent.
The number of persons born before Q equals the number born after P. Q is youngest (slot 7), so six people are born before Q; six must then be born after P, which is only possible if P is the oldest, born in 1955.
The difference between the ages of Q and K is 12 years, so their birth years differ by 12. Q = 2003, hence K = 1991 (2003 - 1991 = 12); 2003 + 12 = 2015 is not in the list.
M is 7 years older than N (M's year is 7 less than N's), and N is younger than O (N born after O). The three years still unused are 1967, 1980 and 1987. Only M = 1980 with N = 1987 gives the required 7-year gap, and that forces O = 1967, which correctly leaves N younger than O. No other split of these three years satisfies both clues.
Consistency check on L: had L been 1955, 1967, 1991 or 2003 instead of 1973, the four-slot L-Q span would either run off the timeline or leave Q with no valid 12-year partner for K, or force P out of the oldest slot - so L = 1973 is the only multiple-of-3 placement that survives.
Final timeline (oldest to youngest)
Person | Year | Age |
|---|---|---|
P | 1955 | 69 |
O | 1967 | 57 |
L | 1973 | 51 |
M | 1980 | 44 |
N | 1987 | 37 |
K | 1991 | 33 |
Q | 2003 | 21 |
Cross-check
Between L (1973) and Q (2003) sit M, N, K - exactly three persons. Correct.
Persons before Q = 6, persons after P = 6. Equal. Correct.
Q and K year gap = 2003 - 1991 = 12. Correct.
M (1980) is 7 years older than N (1987), and N (1987) is younger than O (1967). Correct.
Result
M was born in 1980.