Directions: Read the information and answer the given questions. A * B (18m)…

In a coded direction-and-distance puzzle, each linking symbol fixes two things at once: a compass direction and a rule for converting the bracketed figure into the actual displacement it represents. Once every symbol's direction and conversion rule is read off the four defining statements, the whole network of relations can be redrawn on a standard grid (north = up, east = right), and any person's position relative to any other follows by adding displacement vectors along a connecting chain of statements.

1. Read the four defining lines to fix each symbol's direction: '*' = north, '%' = south, '&' = east, '@' = west.

2. Check the conversion rule from the same four lines: 18m to 8m, 24m to 14m, 28m to 18m, 35m to 25m - every bracketed figure is exactly 10m more than the real displacement, so actual distance = bracketed figure minus 10m.

3. Apply this rule to the three statements that connect M to P: O @ P (32m) gives O is 22m west of P; N & O (36m) gives N is 26m east of O; M * N (16m) gives M is 6m north of N.

4. Fix P at the origin (0, 0). Since O is 22m west of P, place O at (-22, 0).

5. Since N is 26m east of O, N is at (-22 + 26, 0) = (4, 0) - so N is 4m east of P.

6. Since M is 6m north of N, M is at (4, 0 + 6) = (4, 6) - so M is 4m east and 6m north of P.

7. A point that is both to the east and to the north of the origin, with neither component zero, lies in the compass direction lying between due east and due north of that origin.

Re-checking just the east-west chain independently confirms this: the 22m westward leg (O to P) and the 26m eastward leg (N to O) combine to a net eastward shift from P to N, and the purely north-south leg (N to M) only ever adds a vertical shift on top of that - it cannot cancel or reverse the horizontal shift. So M can never end up purely north, or west, or south of P; the displacement must carry both an eastward and a northward part.

M lies to the Northeast of P.