Shyam walked 20 metres towards south. Then he turned to his left and walked 15…

Concept: In direction-sense problems, track the walker's facing direction using compass bearings — North = 0°, East = 90°, South = 180°, West = 270°, increasing clockwise. A left turn subtracts 90° from the current bearing and a right turn adds 90° to it. Convert every leg of the walk into an East-West and North-South displacement, then find the net distance from the start using the distance formula.

1. Start at the origin, facing South (bearing 180°). Walking 20 m south moves the position from (0, 0) to (0, −20).

2. Turning left changes the bearing to 180° − 90° = 90° (East). Walking 15 m east moves the position to (15, −20).

3. Turning left again changes the bearing to 90° − 90° = 0° (North). Walking 20 m north moves the position to (15, 0).

4. Turning right changes the bearing to 0° + 90° = 90° (East). Walking 10 m east moves the position to (25, 0).

Cross-check: The final position (25, 0) shares the same north-south coordinate as the start, so the two south/north legs (20 m each) cancel exactly, leaving the two east legs to combine as 15 m + 10 m = 25 m. The straight-line distance √(25² + 0²) = 25 m confirms a purely eastward displacement with no residual north-south offset.

Result: Shyam ends up 25 metres east of his starting point.