Direction : The table given below shows the data about track record of car…
2021
Direction : The table given below shows the data about track record of car racing game, where 4 cars P, Q, R and S are competing to reach finishing line which is at a distance of 3000 m from their initial starting point.
1. Drift refers to over starting intentionally done by driver.
2. While calculating average speed, do not consider time taken in drift/crash.
3. Points = 50 × drifts – 20 × crashed
Another car named T, makes total number of drifts same as that of car R and it still receives 0 points at the end. How many crashes must car T have suffered?
- A.
15
- B.
18
- C.
21
- D.
12
- E.
20
Show answer & explanation
Correct answer: A
Concept
The scoring rule fixes a points total as a linear combination of two counts: Points = 50 × (drifts) − 20 × (crashes). When a car ends with exactly 0 points, the positive contribution from its drifts is exactly cancelled by the negative contribution from its crashes, so 50 × (drifts) = 20 × (crashes). Reading the required count off a table first means pulling the correct row's value, not any nearby row's.
Application
Car T is told to make the same number of drifts as car R. From the R row of the table, R has 6 drifts, so car T also has 6 drifts.
Substitute into the rule with the final total set to 0: 50 × 6 − 20 × c = 0, where c is the number of crashes.
The drift term is 50 × 6 = 300, so 300 − 20 × c = 0, giving 20 × c = 300.
Divide both sides by 20: c = 300 ÷ 20 = 15 crashes.
Cross-check
Put c = 15 back into the rule: 50 × 6 − 20 × 15 = 300 − 300 = 0 points, which matches the stated condition exactly. The crash and time columns of the table are not needed here — only R's drift count drives the calculation.