Suppose we want to download text documents at the rate of 10 pages per second.…
Suppose we want to download text documents at the rate of 10 pages per second. Assume that a page consists of an average of 24 lines with 80 characters in each line. What is the required bit rate of the channel?
Answer: C. 153600 bps — Calculation: Characters per page = 24 lines × 80 characters = 1,920 characters Bits per page = 1,920 characters × 8 bits/character = 15,360 bits Bits per…
- A.
1.536 Gbps
- B.
1.536 bps
- C.
153600 bps
- D.
1.536 Mbps
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Correct answer: C
Calculation:
Characters per page = 24 lines × 80 characters = 1,920 characters
Bits per page = 1,920 characters × 8 bits/character = 15,360 bits
Bits per second = 10 pages/second × 15,360 bits/page = 153,600 bits/second
Convert to kilobits: 153,600 bits/s = 153.6 kbps (using 1 kbps = 1,000 bits/s)
Answer: 153,600 bits per second (153.6 kbps). The option text "153600 bps" matches this result.