Let A = 1111 1010 arid B = 0000 1010 be two 8-bit 2's complement numbers.…

2004

Let A = 1111 1010 arid B = 0000 1010 be two 8-bit 2's complement numbers. Their product in 2's complement is

Answer: A. 1100 0100Step 1: Convert each 8-bit two's complement operand to decimal. 1111 1010 → invert bits → 0000 0101 (5), add 1 → 0000 0110 (6) → value = -6. 0000 1010 →…

  1. A.

    1100 0100

  2. B.

    1001 1100

  3. C.

    1010 0101

  4. D.

    1101 0101

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Correct answer: A

Step 1: Convert each 8-bit two's complement operand to decimal.

  • 1111 1010 → invert bits → 0000 0101 (5), add 1 → 0000 0110 (6) → value = -6.

  • 0000 1010 → already positive → value = +10.

Step 2: Multiply the decimal values.

  • -6 × 10 = -60.

Step 3: Convert -60 to 8-bit two's complement.

  • Start with +60: 0011 1100.

  • Invert bits → 1100 0011. Add 1 → 1100 0100.

Result: 1100 0100

Therefore, the product of 1111 1010 and 0000 1010 in 8-bit two's complement representation is 1100 0100.

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