Study the following code fragment and answer every sub-part exhaustively. a =…

(i) Output Prediction

Statement 1

print(type(int(a) + int(b) + int(c)))

Calculation

• int(a) → 6

• int(b) → 3

• int(c) → 1

6+3+1=10

Output

<class 'int'>

Statement 2

print(a * int(b))

Calculation

• a = '6'

• int(b) → 3

String multiplication repeats the string 3 times.

Output

666

Statement 3

print(int(a) == b)

Calculation

• int(a) → 6

• b → 3.7

6==3.7

Output

False

Statement 4

print(bool(a), bool(0), bool(''), bool(' '), bool([]))

Output

True False False True False

Reason

• Non-empty string → True

• 0 → False

• Empty string → False

• String with space → True

• Empty list → False

(ii) Two Ways to Round b

b = 3.7

print(round(b))
print(int(b + 0.5))

Output

4
4

(iii) Why No TypeError Occurs

int(a) == b

Python allows comparison between integers and floating-point numbers because both are numeric data types.

• int(a) becomes integer 6

• b is float 3.7

Python automatically compares their numeric values. Since the values are different, the result becomes:

False

No TypeError occurs because numeric types are compatible for comparison.

(iv) Are Both Expressions Same?

Expression 1

int(a) + int(b) + int(c)

Result

6 + 3 + 1 = 10

Expression 2

int(a + b + c)

This produces an error because:

• a is a string

• b is a float

Python cannot add string and float directly.

Error

TypeError

Therefore, the student's claim is false.

The two expressions do not always give the same result.