In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up…

2025

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

  1. A.

    1/3

  2. B.

    3/4

  3. C.

    7/19

  4. D.

    8/21

Attempted by 30 students.

Show answer & explanation

Correct answer: A

Total number of balls: 8 + 7 + 6 = 21

Favourable outcomes (neither red nor green): blue balls = 7

Probability: P = favourable / total = 7 / 21 = 1/3

  • Step 1: Compute total balls = 8 + 7 + 6 = 21.

  • Step 2: Count favourable outcomes (neither red nor green) = number of blue balls = 7.

  • Step 3: Probability = 7 / 21 = 1/3.

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