Akilesh travelled from a point X straight to Y at a distance of 80 m. He…

Concept: In a direction-sense problem, each leg of the walk is a displacement in a fixed direction, and every "turn right" rotates that direction by 90° clockwise. The net distance from the start depends only on how the displacements add up along each axis — two equal legs in exactly opposite directions cancel out, while legs along the same axis in the same direction combine.

1. Take the first leg X → Y (80 m) as pointing East; each subsequent right turn rotates the direction 90° clockwise: East → South → West → North.

2. Leg 2, Y → A: turning right from East gives South, so Akilesh walks 50 m South.

3. Leg 3, A → B: turning right from South gives West, so he walks 70 m West.

4. Leg 4, B → C: turning right from West gives North, so he walks 50 m North.

5. The 50 m South and 50 m North legs are equal and opposite, so they cancel out vertically. Horizontally, the 80 m East leg and the 70 m West leg are opposite, leaving a net displacement of (80 − 70) = 10 m East of the start.

Cross-check: plotting the path shows X, Y and the final point C all lying on the same horizontal line, with C exactly 10 m from X — matching the figure below.

So Akilesh's final distance from the starting point X is 10 m.