The inorder and preorder Traversal of binary Tree are dbeafcg and abdecfg…

Given traversals:

• Preorder: abdecfg

• Inorder: dbeafcg

Step 1: Identify the root from preorder. The first preorder element is 'a', so 'a' is the root.

Step 2: Split the inorder sequence around the root 'a' to find left and right subtrees.

• Left inorder (nodes left of 'a'): d b e

• Right inorder (nodes right of 'a'): f c g

Step 3: Use preorder to get subtree roots and orders.

• After removing root 'a' from preorder, the next elements for the left subtree are 'b d e'. So left subtree root is 'b', with left child 'd' and right child 'e'. Postorder of left subtree is 'd e b'.

• The remaining preorder elements 'c f g' correspond to the right subtree with root 'c', left child 'f' and right child 'g'. Postorder of right subtree is 'f g c'.

Step 4: Combine left subtree postorder, right subtree postorder, and then the root to get the full postorder.

Left subtree postorder: deb

Right subtree postorder: fgc

Full postorder: debfgca