Solve the following question and choose the correct alternative from the…

Concept: In direction-sense problems, treat compass bearing as increasing clockwise from North — North = 0°, East = 90°, South = 180°, West = 270°. A clockwise turn of θ° adds θ to the current bearing; an anti-clockwise turn of θ° subtracts θ from the current bearing (taken mod 360°). A bearing between 0° and 90° is North-East, between 90° and 180° is South-East, between 180° and 270° is South-West, and between 270° and 360° is North-West.

1. Mohan starts facing North, so his initial bearing is 0°.

2. He turns 270° anti-clockwise: bearing = 0° − 270° = −270°, which is equivalent to 90° (mod 360°) — this is due East.

3. He then turns 45° clockwise from this heading: bearing = 90° + 45° = 135°.

4. A bearing of 135° falls strictly between 90° (East) and 180° (South), i.e., in the South-East sector.

Cross-check: an anti-clockwise turn of 270° is the same rotation as a clockwise turn of 360° − 270° = 90°. Turning 90° clockwise from North independently confirms the East heading reached above, and the subsequent 45° clockwise turn from East lands at 135°, i.e., South-East — matching the diagram.

Result: Mohan is facing South-East after the second turn.