In simple interest what sum amounts of Rs 1088 in 6 years and Rs 1184 in 8…

Answer: Rs 800

Key idea: The difference between the two given amounts for 8 years and 6 years gives the simple interest for 2 years.

Compute the annual simple interest:

1. Difference for 2 years = 1184 - 1088 = 96, so simple interest for 1 year = 96/2 = 48.

2. Let the principal be x. Amount after 6 years = x + 6×(annual interest) = x + 6×48.

3. Set this equal to the given amount after 6 years: x + 6×48 = 1088 ⇒ x + 288 = 1088 ⇒ x = 1088 - 288 = 800.

Verification: Amount after 8 years = 800 + 8×48 = 800 + 384 = 1184, which matches the given value.