If two dice are thrown , what is the probability that at least one of them…

Key idea: Use the complement rule: find the probability that neither die shows a number greater than 3, then subtract from 1.

• Step 1: Probability a single die shows a number greater than 3 (i.e., 4, 5, or 6) is 3/6 = 1/2.

• Step 2: Probability neither die shows a number greater than 3 is (1/2) × (1/2) = 1/4.

• Step 3: Probability at least one die shows a number greater than 3 = 1 − 1/4 = 3/4 = 0.75.

Alternative counting method:

• Total possible outcomes when throwing two dice = 6 × 6 = 36.

• Outcomes where both dice show 3 or less = 3 × 3 = 9.

• Favourable outcomes = 36 − 9 = 27, so probability = 27/36 = 3/4 = 0.75.

Final answer: 0.75